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2.5x^2=4.75x-2.2
We move all terms to the left:
2.5x^2-(4.75x-2.2)=0
We get rid of parentheses
2.5x^2-4.75x+2.2=0
a = 2.5; b = -4.75; c = +2.2;
Δ = b2-4ac
Δ = -4.752-4·2.5·2.2
Δ = 0.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.75)-\sqrt{0.5625}}{2*2.5}=\frac{4.75-\sqrt{0.5625}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.75)+\sqrt{0.5625}}{2*2.5}=\frac{4.75+\sqrt{0.5625}}{5} $
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